Question

If $B_{H}=\frac{1}{\sqrt{3}} B_{V}$, find angle of dip. (where symbols have their usual meanings)

• A. $60^{\circ}$
• B. $30^{\circ}$
• C. $45^{\circ}$
• D. $90^{\circ}$

Answer 1

Answer: (A)

$60^{\circ}$

Answer 2

Magnetic dip or magnetic inclination at a place is defined as the angle which the direction of total strength of earths magnetic field makes with a horizontal line in magnetic meridian.
It is the angle by which total intensity of earths magnetic field dips or comes up out of the horizontal plane. It is represented by $8$.
Magnetic dip or magnetic inclination is given by,
$\tan \delta=\frac{B_{V}}{B_{H}} \ldots$ (i)
where $B_{V}$ and $B_{H}$ are vertical and horizontal components of earths magnetic field, respectively
Given, $B_{H}=\frac{1}{\sqrt{3}} B_{V}$
$\therefore \frac{B_{V}}{B_{H}}=\sqrt{3} \ldots$ (ii)
From Eqs. (i) and (ii), we get
$\tan \delta=\sqrt{3}$
$\therefore \delta=60^{\circ}$