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Question: If \(A(x_{1},y_{1}),\mspace{6mu} B(x_{2},y_{2})\) and \(C(x_{3},y_{3})\) are the vertices of a trian...

If A(x1,y1), 6muB(x2,y2)A(x_{1},y_{1}),\mspace{6mu} B(x_{2},y_{2}) and C(x3,y3)C(x_{3},y_{3}) are the vertices of a triangle, then the excentre with respect to B is.

A

(ax1−bx2+cx3a−b+c,ay1−by2+cy3a−b+c)\left( \frac{ax_{1} - bx_{2} + cx_{3}}{a - b + c},\frac{ay_{1} - by_{2} + cy_{3}}{a - b + c} \right)

B

(ax1+bx2−cx3a+b−c,ay1+by2−cy3a+b−c)\left( \frac{ax_{1} + bx_{2} - cx_{3}}{a + b - c},\frac{ay_{1} + by_{2} - cy_{3}}{a + b - c} \right)

C

(ax1−bx2−cx3a−b−c,ay1−by2−cy3a−b−c)\left( \frac{ax_{1} - bx_{2} - cx_{3}}{a - b - c},\frac{ay_{1} - by_{2} - cy_{3}}{a - b - c} \right)

D

None of these

Answer

(ax1−bx2+cx3a−b+c,ay1−by2+cy3a−b+c)\left( \frac{ax_{1} - bx_{2} + cx_{3}}{a - b + c},\frac{ay_{1} - by_{2} + cy_{3}}{a - b + c} \right)

Explanation

Solution

It is obvious