Question

If Avogadro’s number is 6 × 10²³ then the number of protons, neutrons and electrons in 14 g of ₆C¹⁴ are respectively

• A. 36 × 10²³, 48 × 10²³, 36 × 10²³
• B. 36 × 10²³, 36 × 10²³, 36 × 10²¹
• C. 48 × 10²³, 36 × 10²³, 48 × 10²¹
• D. 48 × 10²³, 48 × 10²³, 36 × 10²¹

Answer 1

Answer: (A)

36 × 10²³, 48 × 10²³, 36 × 10²³

Answer 2

Since the number of protons, neutrons and electrons in an atom of $6C^{14}$ are 6, 8 and 6 respectively. As 14 gm of $6C^{14}$ contains 6 × 10²³ atoms, therefore the numbers of protons, neutrons and electrons in 14 gm of $6C^{14}$ are

$6 \times 6 \times 10^{23} = 36 \times 10^{23}$, $8 \times 6 \times 10^{23} = 48 \times 10^{23}$ ,

$6 \times 6 \times 10^{23} = 36 \times 10^{23}$.