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Question

Physics Question on Waves

If at same temperature and pressure, the densities for two diatomic gases are d1d_1 and d2d_2 respectively, then the ratio of velocities of sound in these gases will be

A

d22d1\sqrt{\frac{d_{2}}{2d_{1}}}

B

d2d1\sqrt{\frac{d_{2}}{d_{1}}}

C

2d1d2\sqrt{\frac{2d_{1}}{d_{2}}}

D

d1d2\sqrt{\frac{d_{1}}{d_{2}}}

Answer

d2d1\sqrt{\frac{d_{2}}{d_{1}}}

Explanation

Solution

The velocity of sound in a gas is given by v=γpdv=\sqrt{\frac{\gamma p}{d}} where γ=CPCV\gamma=\frac{C_{P}}{C_{V}} p=p= pressure d=\,\,\,\,\,\, d= density \therefore For two gases at constant pressure, v1v2=d2γ1d1γ2\frac{v_{1}}{v_{2}}=\sqrt{\frac{d_{2} \gamma_{1}}{d_{1} \gamma_{2}}} For a diatomic gas γ1=γ2=75\gamma_{1}=\gamma_{2}=\frac{7}{5} vlv2=d2d1\therefore \frac{v_{ l }}{v_{2}}=\sqrt{\frac{d_{2}}{d_{1}}}