Solveeit Logo
Login

Question

Question: If a<sup>2</sup> + b<sup>2</sup> + c<sup>2</sup> = – 2 and f(x) = \(\left| \begin{matrix} 1 + a^{2}...

If a2 + b2 + c2 = – 2 and

f(x) = ∣1+a2x(1+b2)x(1+c2)x(1+a2)x1+b2x(1+c2)x(1+a2)x(1+b2)x1+c2x∣\left| \begin{matrix} 1 + a^{2}x & (1 + b^{2})x & (1 + c^{2})x \\ (1 + a^{2})x & 1 + b^{2}x & (1 + c^{2})x \\ (1 + a^{2})x & (1 + b^{2})x & 1 + c^{2}x \end{matrix} \right|then f(x) is a

polynomial of degree

A

1

B

3

C

0

D

2

Answer

2

Explanation

Solution

Put a = i, b = i , c = 0

f(x) = ∣1−x0x01−xx001∣\left| \begin{matrix} 1 - x & 0 & x \\ 0 & 1 - x & x \\ 0 & 0 & 1 \end{matrix} \right| = (1– x)2

degree = 2