Question
Question: If a<sup>1/x</sup> = b<sup>1/y</sup> = c<sup>1/z</sup>& a,b,c are in GP; then x,y,z are in –...
If a1/x = b1/y = c1/z& a,b,c are in GP; then x,y,z are in –
A
AP
B
GP
C
HP
D
None
Answer
AP
Explanation
Solution
Put a = 2 ; b = 4 ; c = 8
\ 21/x = 41/y = 81/2 ̃ 21/x = 22/y = 23/2
\ x,y,z are in AP (l- Js.kh)