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Question: If a<sup>1/x</sup> = b<sup>1/y</sup> = c<sup>1/z</sup>& a,b,c are in GP; then x,y,z are in –...

If a1/x = b1/y = c1/z& a,b,c are in GP; then x,y,z are in –

A

AP

B

GP

C

HP

D

None

Answer

AP

Explanation

Solution

Put a = 2 ; b = 4 ; c = 8

\ 21/x = 41/y = 81/2 ̃ 21/x = 22/y = 23/2

\ x,y,z are in AP (l- Js.kh)