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Question: If A<sub>r</sub> = \(\begin{pmatrix} r & r - 1 \\ r - 1 & r \end{pmatrix}\) where r is a natural num...

If Ar = (rr1r1r)\begin{pmatrix} r & r - 1 \\ r - 1 & r \end{pmatrix} where r is a natural number then

|A1| + |A2| + |A3| + ......+ |A2006| must be equal to

A

2006

B

(2006)2

C

(2006)3

D

2007

Answer

(2006)2

Explanation

Solution

|Ar| = r2 –(r –1)2 = 2r –1

Ž |A1| + |A2| + ...... + |A2006|

=r=12006(2r1)\sum_{r = 1}^{2006}{(2r - 1)}= (2006)2