Question

If A₁ is the area of the parabola y² = 4ax lying between vertex and the latus rectum and A₂ is the area between the latus rectum and the double ordinate x = 2a, then $\frac { \mathrm { A } _ { 1 } } { \mathrm {~A} _ { 2 } }$ =

• A. $2 \sqrt { 2 }$ – 1
• B. $\frac { 1 } { 7 } ( 2 \sqrt { 2 } + 1 )$
• C. $\frac { 1 } { 7 } ( 2 \sqrt { 2 } - 1 )$
• D. None

Answer 1

Answer: (B)

$\frac { 1 } { 7 } ( 2 \sqrt { 2 } + 1 )$

Answer 2

A₁ = 2

A₂ =

̃ $\frac { \mathrm { A } _ { 1 } } { \mathrm {~A} _ { 2 } } = \frac { 1 } { 2 \sqrt { 2 } - 1 } = \frac { 2 \sqrt { 2 } + 1 } { 7 }$