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Question: If \[\arg z = \theta \] , then \[\arg \overline z = \] A) \[\theta - \pi \] B) \[\pi - \theta ...

If argz=θ\arg z = \theta , then argz=\arg \overline z =
A) θπ\theta - \pi
B) πθ\pi - \theta
C) θ\theta
D) θ- \theta

Explanation

Solution

Any complex number zz can be written as z=cosθ+isinθz = \cos \theta + i\sin \theta ,where θ\theta is called the argument of zz which is defined as the angle between the positive real axis and the line joining the origin and the point. Also, z\overline z is called the conjugate of zz . The conjugate of zz has the same real part but the imaginary part with the opposite sign .i.e. if z=x+iyz = x + iy then z=xiy\overline z = x - iy . Now, in this question, we need to find the value of the argument of z\overline z . So, we will first write z=cosθ+isinθz = \cos \theta + i\sin \theta and then find its conjugate. After finding the conjugate of zz , we will write z\overline z as z=cosϕ+isinϕ\overline z = \cos \phi + i\sin \phi , where ϕ\phi is the argument of z\overline z .

Complete answer:
We are given argz=θ\arg z = \theta
\therefore , zz can be written as z=cosθ+isinθz = \cos \theta + i\sin \theta
Let us suppose argz=ϕ\arg \overline z = \phi
We now find the conjugate of zz i.e. z\overline z
Now, since z=cosθ+isinθz = \cos \theta + i\sin \theta
z=cosθisinθ\overline z = \cos \theta - i\sin \theta ------(1)
Now, we have to write z\overline z as z=cosϕ+isinϕ\overline z = \cos \phi + i\sin \phi
From (1)
z=cosθ+i(sinθ)\therefore \overline z = \cos \theta + i( - \sin \theta ) -------(2)
We know,
cos(θ)=cosθ\cos ( - \theta ) = \cos \theta
sin(θ)=sinθ\sin ( - \theta ) = - \sin \theta
So, (2) can be written as
z=cos(θ)+isin(θ)\overline z = \cos ( - \theta ) + i\sin ( - \theta )
Now, comparing z=cos(θ)+isin(θ)\overline z = \cos ( - \theta ) + i\sin ( - \theta ) and z=cosϕ+isinϕ\overline z = \cos \phi + i\sin \phi , we get
ϕ=θ\phi = - \theta
argz=ϕ=θ\therefore \arg \overline z = \phi = - \theta
Hence, we get ,
If argz=θ\arg z = \theta , then argz=θ\arg \overline z = - \theta
Therefore, option (D) is the correct answer.

Note:
We need to take care of the fact that zz is always written as z=cosθ+isinθz = \cos \theta + i\sin \theta ,i.e. there is always a ‘+’ sign in between and not ‘-‘ sign. Also, we should know that cos(θ)=cosθ\cos ( - \theta ) = \cos \theta and sin(θ)=sinθ\sin ( - \theta ) = - \sin \theta . While comparing the given condition and the obtained condition we need to take care of the sign. We can also use the formula for finding the argument of zz i.e. if z=x+iyz = x + iy , then argz=tan1yx\arg z = {\tan ^{ - 1}}\dfrac{y}{x} .