Question
Question: If \[\angle x = {30^ \circ }\], then \[\tan 2x = \dfrac{{2\tan x}}{{1 - {{\tan }^2}x}}\] If true...
If ∠x=30∘, then
tan2x=1−tan2x2tanx
If true enter 1 else 0
Solution
To solve this question first solve the right-hand side of the equation by putting the value ∠x=30∘ then simplify that equation to come to the shortest answer that is possible. Then put the value on the left-hand side and find the value after putting that value. If both the sides are equal then enter 1 and if they are not equal. Then enter 0.
Complete answer:
Given,
Angle x is given ∠x=30∘and the expression is also given tan2x=1−tan2x2tanx
To, solve this question first solve right hand side of the equation by putting the value ∠x=30∘
The right hand side of the equation is
RHS=1−tan2x2tanx
On putting the value of x
⇒1−tan2302tan(30)
We know that value of tan30=31 on putting this value
⇒1−(31)2231
On further solving
⇒1−3132
On taking LCM in denominator
⇒33−132
On further solving
⇒32×23
⇒3
The value of left hand side of the equation:
RHS=3 ……(i)
On putting the value of x in left hand side
LHS=tan2x
⇒tan(2×30)
⇒tan(60)
We know that tan(60∘)=3
On putting this value we get value of left hand side
LHS=3 ……(ii)
From equation (i) and (ii) the value of LHS and RHS are equal to we enter 1
Final answer:
From equations (i) and (ii) we get that the left-hand side and right-hand side both are equal.
Note:
To solve these types of questions we have to directly put the value in the given expression and find their values on the left-hand side and right-hand side. If both the sides are equal then the condition is true and if they are not equal then that condition is not true.