Solveeit Logo

Question

Mathematics Question on Vector Algebra

If angle between i2j+3k\overrightarrow{i}-2\overrightarrow{j}+3\overrightarrow{k} and 2i+j+3k2\overrightarrow{i}+\overrightarrow{j}+3\overrightarrow{k} is θ\theta then sinθ\sin\theta is equal to

A

57\frac{5}{\sqrt7}

B

521\frac{5}{21}

C

527\frac{5}{2\sqrt7}

D

514\frac{5}{\sqrt14}

Answer

527\frac{5}{2\sqrt7}

Explanation

Solution

The correct option is (C): 527\frac{5}{2\sqrt7}