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Question: If an integer is chosen at random from first 100 positive integers, then the probability that the ch...

If an integer is chosen at random from first 100 positive integers, then the probability that the chosen number is a multiple of 4 or 6, is

A

41/100

B

33/100

C

1/10

D

None

Answer

33/100

Explanation

Solution

Let A be the event to be multiple of 4 and B be the event to the multiple of 6.

So, P(1) = 25/100, P(2) = 16/100 and P(AĒB) = 8/100

Thus required probability is P(AUB)

= P(1) + P(2) – P(AĒB)

Ž P(AUB) = 25100+16100−8100=33100\frac { 25 } { 100 } + \frac { 16 } { 100 } - \frac { 8 } { 100 } = \frac { 33 } { 100 }