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Question

Physics Question on Electric Field

If an insulated non-conducting sphere of radius RR has charge density ρ.\rho . The electric field at a distance r from the centre of sphere (r>R)(r > R) will be:

A

ρR3ε0\frac{\rho R}{3 \varepsilon_{0}}

B

ρrε0\frac{\rho r}{\varepsilon_{0}}

C

ρr3ε0\frac{\rho r}{3 \varepsilon_{0}}

D

3ρRε0\frac{3 \rho R}{\varepsilon_{0}}

Answer

ρr3ε0\frac{\rho r}{3 \varepsilon_{0}}

Explanation

Solution

Charge which is enclosed in the surface is given by
σ=43πr3ρ\sigma=\frac{4}{3} \pi r^{3} \rho
Now according to Gaussian law
εϕEds=σ,\varepsilon \,\phi\, E d s=\sigma,
ε0E4πr2=43πr3ρ\varepsilon_{0} E 4 \pi r^{2}=\frac{4}{3} \pi r^{3} \rho
E=ρr3ε0E=\frac{\rho r}{3 \varepsilon_{0}}