Question

If an electron in n = 3 orbit of hydrogen atom jumps down to n = 2 orbit, the amount of energy released and the wavelength of radiations emitted are –

• A. 0.85 eV, 6566Å
• B. 1.89 eV, 1240Å
• C. 1.89 eV, 6566Å
• D. 1.5 eV, 6566 Å

Answer 1

Answer: (C)

1.89 eV, 6566Å

Answer 2

E = – 1.51 eV – (– 3.4 eV)

\ E = 1.89 eV

and l = $\frac{12400}{1.89}$Å = 6566 Å