Question
Question: If an electron falls from n=3 to n=2, then how much energy is released? A. 10.2 eV B. 12.09 eV ...
If an electron falls from n=3 to n=2, then how much energy is released?
A. 10.2 eV
B. 12.09 eV
C. 1.9 eV
D. 0.65 eV
Solution
This question is related to Bohr’s postulates.
When an electron jumps from higher energy orbital to lower energy orbital, it releases a photon of the energy equal to the difference in energy of the orbitals. Energy of nth orbital in a hydrogen atom is inversely proportional to square of n.
Formula used:
Energy of nth orbital in hydrogen atom, En=n2−13.6eV
Complete step by step answer:
In 1913, Bohr proposed that electrons in an atom revolve around certain orbits known as stationary orbits. The energy of these orbits are constant and is given by
En=n2−13.6eV
Where n is principal quantum number of the orbit
Energy of an electron decreases when it jumps from a higher orbital to lower orbital. So following law of conservation of energy, a photon of energy equivalent to change in energy of electron, is released.
When electron jumps from 3rd orbit to the 2nd orbit, change in its energy
ΔE3 to 2=−13.6(221−321)=−13.6(365)
ΔE3 to 2=−1.9eV
When an electron jumps from higher orbital to lower orbital, a photon of energy equal to change in energy of electron is released. Therefore energy released by electron is 1.9 eV
So, the correct answer is “Option C”.
Additional Information:
When electron jumps from higher orbit (ni ) to lower orbit ( nf ) then, wavelength of emitted photon is given by
λ1=R(nf21−ni21)
Where R is Rydberg’s constant.
Note: Energy of each orbit is a constant. Energy of an electron in any orbital is negative. That is why it is bound to an atom.
When electrons gain energy, they move from a lower energy level to a higher energy level of an atom.
The energy of an orbital is usually denoted in electron Volts.