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Question

Mathematics Question on Sets

If aN=ax:xNaN = {ax : x \in N} and bNcN=dNbN \cap cN = dN, where b,cNb,\, c \in N are relatively prime, then

A

d=bcd = bc

B

c=bdc = bd

C

b=cdb = cd

D

None of these

Answer

d=bcd = bc

Explanation

Solution

bN = {bx:xNbx : x \in N} cN = {cx:xNcx : x \in N} bNcN=\therefore bN \cap cN = {x : x is multiple of b and c both} == { x: x is multiple of l.c.m. of b and c } == { x : x is multiple of b c} [given b and c are relatively prime \therefore l.c.m. of b and c=bcc = bc] bNcN=bcx:xN=dN\therefore bN \cap cN = {bc x : x \in N} = dN (Given) d=bc.\therefore d = bc.