Question

If an average person jogs, he produces 14.5 × 104 cal min-1. This is removed by the evaporation of sweat. The

amount of sweat evaporated per minute (assuming 1 kg requires 580 × 103 cal for evaporation) is

• A. 0.25 kg
• B. 2.25 kg
• C. 0.05 kg
• D. 0.20 kg

Answer 1

Answer: (A)

0.25 kg

Answer 2

Amount of sweat evaporated per minute

$= \frac{caloriesproducedper\min ute}{no.ofcaloriesrequiredforevaportionperkg} = \frac{14.5 \times 10^{4}}{580 \times 10^{3}} = 0.25kg$