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Question: If an aqueous solution at 25oC has twice as many OH- as pure water its pOH will be...

If an aqueous solution at 25oC has twice as many OH- as pure water its pOH will be

A

6.699

B

7.307

C

7

D

6.98

Answer

6.699

Explanation

Solution

[OH−]=2×10−7\left\lbrack OH^{-} \right\rbrack = 2 \times 10^{- 7}

pOH=14−pHor−log⁡[OH−]pOH = 14 - pHor - \log\left\lbrack OH^{-} \right\rbrack