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Question: If AM and GM of two positive numbers a and b are 10 and 8 respectively, find the numbers...

If AM and GM of two positive numbers a and b are 10 and 8 respectively, find the numbers

Explanation

Solution

Hint: we need to know the general formula of Arithmetic and Geometric means of two numbers.
It is given that a and b are two numbers.
Arithmetic mean (AM) of the given two numbers is a+b2=10\frac{{a + b}}{2} = 10 ... (1)
Geometric Mean (GM) of the given two numbers is ab=8\sqrt {ab} = 8 ... (2)
On simplifying equation (1) and (2), we get
a+b=20\Rightarrow a + b = 20 and ab=64ab = 64
We need to find the unique values of a and b.
Clearly, a and b are roots of the quadratic equation
x2(a+b)x+ab=0{x^2} - (a + b)x + ab = 0
Substituting (a+b)&\left( {a + b} \right)\& ab values
x220x+64=0{x^2} - 20x + 64 = 0
Factorization of the above quadratic equation to find roots
(x16)(x4)=0\Rightarrow (x - 16)(x - 4) = 0
x=4,16\Rightarrow x = 4,16
a=4,b=16\therefore a = 4,b = 16 or a=16,b=4a = 16,b = 4 are the required values.

Note: Arithmetic mean is the sum of a collection of all numbers divided by count of numbers in the collection. Geometric mean indicates the central tendency or typical value of a set of numbers by using the product of their values.