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Question

Mathematics Question on Sequence and series

If α,β\alpha, \beta are the roots of the equation x2x1=0x^2 - x - 1 = 0 and Sn=2023αn+2024βnS_n = 2023 \alpha^n + 2024 \beta^n, then:

A

S12=S1+S10S_{12} = S_1 + S_{10}

B

2S11=S12+S102S_{11} = S_{12} + S_{10}

C

S11=S10+S12S_{11} = S_{10} + S_{12}

D

S1+S10=S12S_1 + S_{10} = S_{12}

Answer

2S11=S12+S102S_{11} = S_{12} + S_{10}

Explanation

Solution

Given:
x2x1=0    α,β are roots.x^2 - x - 1 = 0 \implies \alpha, \beta \text{ are roots.}

The relation between α\alpha and β\beta is:
α2=α+1,β2=β+1.\alpha^2 = \alpha + 1, \quad \beta^2 = \beta + 1.

The sequence SnS_n is defined as:
Sn=2023αn+2024βn.S_n = 2023\alpha^n + 2024\beta^n.

Using the recurrence relation for the roots:
Sn+2=Sn+1+Sn.S_{n+2} = S_{n+1} + S_n.

Applying this for n=10n = 10:
S12=S11+S10.S_{12} = S_{11} + S_{10}.

The Correct answer is: 2S11=S12+S102S_{11} = S_{12} + S_{10}