if aex+bey=c; pex+qey=d and the the value of (x, y) is | Mathematics | SolveeIt

if aex+bey=c; pex+qey=d and

the the value of (x, y) is

$(\frac{△_2}{△_1},\frac{△_3}{△_1})$

$(log\frac{△_2}{△_1},log\frac{△_3}{△_1})$

$(log\frac{△_1}{△_3},log\frac{△_1}{△_2})$

$(log\frac{△_1}{△_2},log\frac{△_1}{△_3})$

Answer

$(log\frac{△_2}{△_1},log\frac{△_3}{△_1})$

Explanation

The correct option is (B): $(log\frac{△_2}{△_1},log\frac{△_3}{△_1})$

Mathematics Question on Exponents