Question

If abscissae & ordinates of ends of diameter of circle are roots of quadratic equation x² + 2x – 1 = 0& x² – 2x – 7 = 0 then sum of length of intercepts made by this circle on axes

• A. $6 \sqrt { 2 }$
• B. $4 \sqrt { 2 }$
• C. 6
• D. 12

Answer 1

Answer: (D)

12

Answer 2

Circle is (x² + 2x – 1) + (y² – 2y – 7) = 0

i.e. x² + y² + 2x – 2y – 8 = 0

Sum of intercepts = $2 \sqrt { \mathrm { f } ^ { 2 } - \mathrm { c } }$=12