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Question

Mathematics Question on Vectors

If ABCD is a parallelogram, vector AB = 2i + 4j - 5k and vector AD = i + 2j + 3k, then the unit vector in the direction of BD is

A

169(i^+2j^8k^)\frac{1}{√69}(\hat{i}+2\hat{j}-8\hat{k})

B

169(i^+2j^8k^)\frac{1}{69}(\hat{i}+2\hat{j}-8\hat{k})

C

169(i^2j^+8k^)\frac{1}{√69}(\hat{-i}-2\hat{j}+8\hat{k})

D

169(i^2j^+8k^)\frac{1}{69}(\hat{-i}-2\hat{j}+8\hat{k})

Answer

169(i^2j^+8k^)\frac{1}{√69}(\hat{-i}-2\hat{j}+8\hat{k})

Explanation

Solution

The correct answer is option C) 169(i^2j^+8k^)\frac{1}{√69}(\hat{-i}-2\hat{j}+8\hat{k})