If a2 + b2 = 14ab, then log ((\frac{a+b}{4}))= | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

If a2 + b2 = 14ab, then log ( $\frac{a+b}{4}$ )=

A

$\frac{1}{2}$ (log a+ log b)

B

$\frac{1}{2}$ log (a)+ log (b)

C

$\frac{1}{2}$ log $(\frac{a}{b})$

D

$\frac{1}{3}$ log $(\frac{a}{b})$

Answer

$\frac{1}{2}$ (log a+ log b)

Explanation

Solution

The correct option is (A): $\frac{1}{2}$ (log a+ log b)