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Question

Mathematics Question on Sequence and series

If ax=by=cza^x = b^y = c^z and a,b,ca, b, c are in G.P. then x,y,zx, y, z are in

A

A.P

B

G.P

C

H.P

D

none of these.

Answer

H.P

Explanation

Solution

ax=by=cz=Ka^{x} =b^{y} = c^{z} = K (say) a=K1x,b=K1y,c=K1z \Rightarrow a= K^{\frac{1}{x}}, b= K^{\frac{1}{y}}, c= K^{\frac{1}{z}}. \Rightarrow Since a,b,ca, b, c are in G.PG.P. b2=ac \Rightarrow b^{2} =ac K2y=K1xK1z=K1x+1z \Rightarrow K^{\frac{2}{y}} = K^{\frac{1}{x}} \cdot K^{\frac{1}{z}} = K^{\frac{1}{x}+\frac{1}{z}} 2y=1x+1z\Rightarrow \frac{2}{y} = \frac{1}{x}+\frac{1}{z} 1x,1y,1z \Rightarrow \frac{1}{x} , \frac{1}{y}, \frac{1}{z} are in A.PA.P. x,y,z \Rightarrow x, y, z are in H.PH.P.