Question

If a wire of resistance R is connected across Vo, then power is Po. The wire is cut into two equal parts and connected with Vo individually, then the sum of power dissipated is P1, then $\frac{Po}{Pi}$ is $\frac{1}{x}$. Find the value of x.

Answer 1

$\text{The value of x}$ :

$P_0=(\frac{V_0^2}{R})$

$P_i=\frac{V_0^2}{\frac{R}{2}}+\frac{V_0^2}{\frac{R}{2}}=\frac{4V_0^2}{R}$

$\frac{P_0}{P_i}=\frac{1}{x}=\frac{1}{4}$

$\therefore \;x=4$

$\text{The correct answer is 4.}$