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Question: If a velocity has both perpendicular and parallel components when moving through a magnetic field, t...

If a velocity has both perpendicular and parallel components when moving through a magnetic field, the path followed by a charged particle is:
(A) Circular
(B) Elliptical
(C) Linear
(D) Helical

Explanation

Solution

Hint A particle moving in a magnetic field will experience force only if the magnetic field is perpendicular to it. This is because the force on a particle in a magnetic field is the cross product of velocity and direction of the magnetic field.

Complete step by step solution
When a particle is moving in a magnetic field, it experiences force according to the given formula
F=q(v×B)F\, = \,q(v\, \times B)
F=qvBsinθF\, = \,qvB\sin \theta
Where θ\theta is the angle between the velocity and the magnetic field.
This force will act perpendicular to the direction of motion of the particle. This centripetal force will be equal to

mv2r=qvB v=qrBm  \dfrac{{m{v^2}}}{r}\, = \,qvB \\\ v\, = \,\dfrac{{qrB}}{m} \\\

Thus this force will make the particle move in a circular path. Whereas there will be no external force acting on the particle in the direction of the magnetic field. The resultant of these 2 forces will make the particle move in a helical path.

Therefore the correct answer is option D.

Note This concept is used in a particle accelerator, where the magnetic field rotates the particle in a circular motion and the electric field speeds up the particle.