Solveeit Logo

Question

Physics Question on Motion in a plane

If a vector A\vec{A} makes an angles α\alpha, β\beta and γ\gamma respectively with the xx, yy and zz axes respectively. Then sin2α+sin2β+sin2γsin^{2}\alpha+sin^{2}\beta+sin^{2}\gamma is equal to

A

00

B

11

C

22

D

33

Answer

22

Explanation

Solution

cos2α+cos2β+cos2γ=1 cos^{2}\,\alpha+cos^{2}\,\beta+cos^{2}\,\gamma=1 (1sin2α)+(1sin2β)+(1sin2γ)=1\left(1-sin^{2}\,\alpha\right)+\left(1-sin^{2}\beta\right)+\left(1-sin^{2}\gamma\right)=1 or sin2α+sin2β+sin2γ=31=2sin^{2}\alpha+sin^{2}\beta+sin^{2}\gamma=3-1=2