Question
Question: If a vector has an X- component of \( - 25\) units and a Y- component of \(40\) units, then the magn...
If a vector has an X- component of −25 units and a Y- component of 40 units, then the magnitude and direction of this vector are:
A) 589units;sin−189−5withx - axis
B) 589units;cos−189−5withx - axis
C) 45units;cos−19−5withx - axis
D) 45units;sin−19−5withx - axis
Solution
The magnitude of a vector is the square root of the sum of components of X- direction, Y- direction, and Z- direction. And the quadrant where the vector belongs has to be found. Thus the angle of the vector made with the X-axis can be found by using the tangent function.
Complete step by step answer:
Given the X-component of the vector is −25 units and the Y- component of the vector is 40 units.
The expression for the magnitude of the vector having X- component and Y- component is given as,
X2+Y2
Thus the magnitude of the vector by substituting the values in the above expression gives
(−25)2+402=2225 =25×89 =589units
Thus the magnitude of the vector is 589units.
The angle the vector makes with the horizontal line can be defined as the direction of the vector.
And, the angle the vector makes with the X-axis is given as,
The sign of the X- component is negative and the sign of Y- component is positive. It implies that the vector is in the second quadrant. Thus the angle it makes with the X-axis is
θ=tan−1(xy) =tan−1(−2540) =tan−1(−58) =cos−189−5
Therefore the angle it made with the X- axis is cos−189−5. Hence, the answer is option B.
Note:
The X- component of the vector will be the unit that makes the vector to left or right. And, the Y- component of the vector will be the unit that makes the vector up or down. And the direction depends on both the components.