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Question

Question: If \(A \times B = \\{ (a,x),(a,y),(b,x),(b,y)\\} \). Find A and B....

If A×B=(a,x),(a,y),(b,x),(b,y)A \times B = \\{ (a,x),(a,y),(b,x),(b,y)\\} . Find A and B.

Explanation

Solution

At first using the formulaP×Q=(p,q):pP,qQP \times Q = \\{ (p,q):p \in P,q \in Q\\} we will find elements that belongs to sets A and B respectively. Then using those elements we will find the particular set i.e. A and B and finding those sets is the task we need to get the answer.

Complete step by step solution: Given data: A×B=(a,x),(a,y),(b,x),(b,y)A \times B = \\{ (a,x),(a,y),(b,x),(b,y)\\}
Now we know that if we have two sets let P and Q then
(P×Q)(P \times Q) is defined as a relation, (PQ)(P \to Q) where the elements of (P×Q)(P \times Q) will be in the form (p,q) where
pPp \in P and qQq \in Q.
P×Q=(p,q):pP,qQP \times Q = \\{ (p,q):p \in P,q \in Q\\}
Therefore from the given data i.e. A×B=(a,x),(a,y),(b,x),(b,y)A \times B = \\{ (a,x),(a,y),(b,x),(b,y)\\}
We can say that a,bAa,b \in A and, x,yBx,y \in B
Therefore from the above statement, we can say that

A=a,bA = \\{ a,b\\} , And B=x,yB = \\{ x,y\\}

Note: We know that if two sets let X and Y have m and n numbers of elements respectively then the number of elements in the sets (X×Y)(X \times Y) or (Y×X)(Y \times X) will be the product of the number of elements in the respective sets i.e. mn.
Therefore we can also verify our answer using the above statement as
n(A×B)=4n(A \times B) = 4
And from the answer we have n(A)=2n(A) = 2 and, n(B)=2n(B) = 2
Since n(B)×n(A)=4n(B) \times n(A) = 4 hence it satisfies the statement we mentioned.