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Question: If \(A{\text{ = }}\left\\{ {{\text{a,b}}} \right\\}{\text{ }}\) and \(B = \left\\{ {1,2,3} \right\\}...

If A{\text{ = }}\left\\{ {{\text{a,b}}} \right\\}{\text{ }} and B = \left\\{ {1,2,3} \right\\}. Find A×AA \times A and B×BB \times B

Explanation

Solution

Hint: In order to find the product of A×AA \times A and B×BB \times B , we have to use the definition of Cartesian product. The Cartesian product of two sets AA and BB , denoted A×BA \times B , is the set of all ordered pairs where aa is in AA and bb is in BB.

Complete step-by-step answer:
In the above question we have to find A×AA \times A and B×BB \times B- Given two sets AA and BB, the Cartesian product is the set of all unique ordered pairs using one element from Set AA and one element from set BB .
For example-
Suppose, a = \left\\{ {{\text{Dog,Cat}}} \right\\}{\text{ }}b = \left\\{ {{\text{Meat,Milk}}} \right\\} then,
A \times B = \left\\{ {\left( {{\text{Dog,Meat}}} \right),\left( {{\text{Cat,Milk}}} \right),\left( {{\text{Dog,Milk}}} \right),\left( {{\text{Cat,Meat}}} \right)} \right\\}
Here, we have -
A = \left\\{ {a,b} \right\\}{\text{ equation}}\left( 1 \right) \\\ B = {\text{ }}\left\\{ {1,2,3} \right\\}{\text{ equation}}\left( 2 \right) \\\ \\\
Now; we have to find A×AA \times A and B×BB \times B . By using the definition of Cartesian product that is-
A \times A{\text{ = }}\left\\{ {a,b} \right\\}{\text{ }} \times {\text{ }}\left\\{ {a,b} \right\\} \\\ \\\
= \left\\{ {\left( {a,a} \right),{\text{ }}\left( {a,b} \right){\text{, }}\left( {b,a} \right),{\text{ }}\left( {b,b} \right)} \right\\}
Similarly,
B \times B =\left\\{ {1,2,3} \right\\}{\text{ }} \times {\text{ }}\left\\{ {1,2,3} \right\\} =\left\\{ {\left( {1,1} \right),{\text{ }}\left( {1,2} \right),{\text{ }}\left( {1,3} \right),{\text{ }}\left( {2,1} \right),{\text{ }}\left( {2,2} \right),{\text{ }}\left( {2,3} \right),{\text{ }}\left( {3,1} \right),{\text{ }}\left( {3,2} \right),{\text{ }}\left( {3,3} \right)} \right\\} \\\
Note: Whenever we face such type of questions, the key concept is that the Cartesian product of AA and BB , denoted A×BA \times B , is the set of all possible ordered pairs where the elements ofAA are first and the elements of BB are second. By using the Cartesian product we will get our required answer like we did in the question.