Question
Question: If \(A{\text{ = }}\left\\{ {{\text{a,b}}} \right\\}{\text{ }}\) and \(B = \left\\{ {1,2,3} \right\\}...
If A{\text{ = }}\left\\{ {{\text{a,b}}} \right\\}{\text{ }} and B = \left\\{ {1,2,3} \right\\}. Find A×A and B×B
Solution
Hint: In order to find the product of A×A and B×B , we have to use the definition of Cartesian product. The Cartesian product of two sets A and B , denoted A×B , is the set of all ordered pairs where a is in A and b is in B.
Complete step-by-step answer:
In the above question we have to find A×A and B×B- Given two sets A and B, the Cartesian product is the set of all unique ordered pairs using one element from Set A and one element from set B .
For example-
Suppose, a = \left\\{ {{\text{Dog,Cat}}} \right\\}{\text{ }}b = \left\\{ {{\text{Meat,Milk}}} \right\\} then,
A \times B = \left\\{ {\left( {{\text{Dog,Meat}}} \right),\left( {{\text{Cat,Milk}}} \right),\left( {{\text{Dog,Milk}}} \right),\left( {{\text{Cat,Meat}}} \right)} \right\\}
Here, we have -
A = \left\\{ {a,b} \right\\}{\text{ equation}}\left( 1 \right) \\\
B = {\text{ }}\left\\{ {1,2,3} \right\\}{\text{ equation}}\left( 2 \right) \\\
\\\
Now; we have to find A×A and B×B . By using the definition of Cartesian product that is-
A \times A{\text{ = }}\left\\{ {a,b} \right\\}{\text{ }} \times {\text{ }}\left\\{ {a,b} \right\\} \\\
\\\
= \left\\{ {\left( {a,a} \right),{\text{ }}\left( {a,b} \right){\text{, }}\left( {b,a} \right),{\text{ }}\left( {b,b} \right)} \right\\}
Similarly,
B \times B =\left\\{ {1,2,3} \right\\}{\text{ }} \times {\text{ }}\left\\{ {1,2,3} \right\\}
=\left\\{ {\left( {1,1} \right),{\text{ }}\left( {1,2} \right),{\text{ }}\left( {1,3} \right),{\text{ }}\left( {2,1} \right),{\text{ }}\left( {2,2} \right),{\text{ }}\left( {2,3} \right),{\text{ }}\left( {3,1} \right),{\text{ }}\left( {3,2} \right),{\text{ }}\left( {3,3} \right)} \right\\} \\\
Note: Whenever we face such type of questions, the key concept is that the Cartesian product of A and B , denoted A×B , is the set of all possible ordered pairs where the elements ofA are first and the elements of B are second. By using the Cartesian product we will get our required answer like we did in the question.