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Question: If a steady current of 4 amp maintained for 40 minutes, deposits 4.5 gm of zinc at the cathode and t...

If a steady current of 4 amp maintained for 40 minutes, deposits 4.5 gm of zinc at the cathode and then the electro chemical equivalent will be

A

51×10−17gm/C51 \times 10^{- 17}gm/C

B

28×10−6gm/C28 \times 10^{- 6}gm/C

C

32×10−5gm/C32 \times 10^{- 5}gm/C

D

47×10−5gm/C47 \times 10^{- 5}gm/C

Answer

47×10−5gm/C47 \times 10^{- 5}gm/C

Explanation

Solution

m=Zitm = Zit ⇒ Z=mit=4.54×40×60=47×10−5g/CZ = \frac{m}{it} = \frac{4.5}{4 \times 40 \times 60} = 47 \times 10^{- 5}g/C