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Question

Physics Question on laws of motion

If a spring of stiffness k'k' is cut into two parts A'A' and B'B' of length A:B=2:3\ell_A : \ell_B = 2 : 3, then the stiffness of spring A'A' is given by :

A

3k5\frac{3k}{5}

B

2k5\frac{2k}{5}

C

kk

D

53k\frac{5}{3k}

Answer

53k\frac{5}{3k}

Explanation

Solution

A=25,B=(35)\ell_{A} = \frac{2\ell}{5},\,\,\ell_{B} = \left(\frac{3\ell }{5}\right) K=KAA=KBBK_{\ell} = K_{A}\ell_{A} = K_{B}\ell_{B} K=KA(25)K\ell = K_{A} \left(\frac{2\ell}{5}\right) KA=5K2KB=5K3.K_{A} = \frac{5K}{2}\quad\quad\quad\Rightarrow\quad K_{B} = \frac{5K}{3}.