Question

If a spark is produced on removing the load from an AC circuit then the element connected in the circuit is
A. high resistance
B. high capacitance
C. high inductance
D. high impedance

Answer 1

The above problem can be resolved using the fundamentals of an inductive circuit and the role of inductance in an AC circuit, where the load on the circuit is reduced. The inductance of the circuit changes according to supply voltage across the terminals of the circuit.

Complete step by step answer:
When an electric circuit is closed, such that there is the flow of charges, constituting the current.
The rate of flow of charge is given as,
$dQ = \dfrac{{di}}{{dt}}.................\left( 1 \right)$
When the load is being removed from the circuit, the current flow is restricted and the charges stop flowing. In this condition, the electrical circuit will act as an open circuit.
Moreover, the condition for the sparking will take place only when the magnitude of voltage becomes higher at the open ends of the circuit. And this condition is possible only in the case of an inductor. Because the voltage drop across the inductor is, $L\dfrac{{di}}{{dt}}$.
Where, L is the inductance of the circuit.
Therefore, if a spark is produced on removing the load from an AC circuit then the element connected in the circuit is of higher inductance

So, the correct answer is “Option C”.

Note:
In order to resolve the given problem, one must try to understand the concept of loading and unloading of an electrical circuit, along with the appropriate effect of the voltage change in each case. The basics of an inductor and the resistor are needed to be taken into consideration for the analysis of the electrical circuits.