QuestionReportMathematics Question on Inverse Trigonometric FunctionsIf a=sin−1(sin 5)a=sin^{-1}(sin\ 5)a=sin−1(sin 5) and b=cos−1(cos 5)b=cos^{-1}(cos\ 5)b=cos−1(cos 5), then a2+b2=a^2+b^2=a2+b2=AnswerThe answer is 8π2−40π+508\pi^2-40\pi+508π2−40π+50.
