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Question: If a simple pendulum makes 20 oscillations in 4 seconds, what is the frequency?...

If a simple pendulum makes 20 oscillations in 4 seconds, what is the frequency?

Explanation

Solution

To do this question we have to use the formula of frequency that is f=1Tf=\dfrac{1}{T}. And have the knowledge of unitary methods. Before moving ahead let's talk about what a unitary method is. Suppose we went to the market and bought 22mangoes for rupees 1010. So what is the price of 55mangoes.
2 mangoes = 1010rupees
1 mango = 102=5\dfrac{10}{2}=5 rupees
5 mangoes =5×5=255\times 5=25rupees

Complete step by step answer:
Simple pendulum: It is fixed with a rigid body and has some mass attached to its string and oscillates into and fro motion.
Oscillation: when one complete to and fro motion is completed by oscillating bodies then it is called oscillation.
Frequency: Number of oscillation per second is called frequency. It's S.I. unit is hertz.
Time period: time taken to complete one oscillation is called its time period.

Now let us calculate the frequency when pendulum makes 20 oscillation in 4 seconds,
20 oscillation = 4 seconds
1 oscillation = 420=15sec\dfrac{4}{20}=\dfrac{1}{5}\sec
So, for single oscillation 15sec\dfrac{1}{5}\sec is taken. so time period of the pendulum 15sec\dfrac{1}{5}\sec .
f=1T\Rightarrow f=\dfrac{1}{T}
f=5Hz\therefore f=5\,Hz

Hence, the frequency is 5 Hz.

Note: If we immerse a simple pendulum in water then it will experience a buoyant force in upward direction. In addition to the other force like gravity and tension.In simple pendulum , we can find the value of equivalent force constant of oscillation keq{{k}_{eq}}=Tl\dfrac{T}{l} ; where TT is the tension in the string at equilibrium position of the bob and O is the length of the string.