Solveeit Logo
Login

Question

Question: If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to \(2.0ms^{...

If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0ms−22.0ms^{- 2} at any time, the angular frequency of the oscillator is equal to

A

10rads−110rads^{- 1}

B

0.1rads−10.1rads^{- 1}

C

100rads−1100rads^{- 1}

D

1rads−11rads^{- 1}

Answer

10rads−110rads^{- 1}

Explanation

Solution

ω=AccelerationDisplacement=2.00.02=10rad 6mus−1\omega = \sqrt{\frac{Acceleration}{Displacement}} = \sqrt{\frac{2.0}{0.02}} = 10rad\mspace{6mu} s^{- 1}