Question
Question: If a semiconductor has an intrinsic carrier concentration of 1.41 × 10<sup>16</sup> m<sup>–3</sup>, ...
If a semiconductor has an intrinsic carrier concentration of 1.41 × 1016 m–3, when doped with 1021 m–3 phosphorus, then the concentration of holes at room temperature will be –
A
2 × 1021
B
2 × 1011
C
1.41 × 1010
D
1.41 × 1016
Answer
1.41 × 1016
Explanation
Solution
Phosphorus is pentavalent impurity. Its doping will not effect the concentration of holes. So number of holes will be equal to same as in intrinsic semiconductor. So nh= 1.41 × 1016 m–3