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Question: If \[a = \sec {2^ \circ }\] and \[b = \sec 2\], then A) \[a = b\] B) \[a < b\] C) \[b < a\] ...

If a=sec2a = \sec {2^ \circ } and b=sec2b = \sec 2, then
A) a=ba = b
B) a<ba < b
C) b<ab < a
D) 2a=b2a = b

Explanation

Solution

In the given question, we have to apply trigonometric identity to arrive at the solution. Since the question is given in degrees, we can solve it by converting it into radians. We can use the trigonometric ratio table to find out the required value.

Complete step by step solution:
Let us understand with the help of diagram:

The diagram shows four quadrants: I, II, III and IV along-with the degrees and their radians at the end of the line segment. All of the even multiples are the quadrantal angles and are reduced, just like any other fraction.
Now a=sec2a = \sec {2^ \circ } is a positive value lying in quadrant I. Therefore, we can conclude that a>0a > 0 i.e. it is a positive value.
Since 180=π{180^ \circ } = \pi , we can conclude that 1=π180{1^ \circ } = \dfrac{\pi }{{180}}
Therefore, multiplying by 22 on both the sides, we will get,
2=π180(2)=π90{2^ \circ } = \dfrac{\pi }{{180}}(2) = \dfrac{\pi }{{90}}
Hence, we can conclude that:
a=sec2=secπ90a = \sec {2^ \circ } = \sec \dfrac{\pi }{{90}}
Now we are given that b=sec2b = \sec 2
We know that π90<2\dfrac{\pi }{{90}} < 2 since the value of π\pi is approximate 3.143.14.
So, we can say that:
sec2>sec2\sec {2^ \circ } > \sec 2
b<a\Rightarrow b < a
Hence, Option (C) b<ab < a is the correct answer.

Note:

  1. We can solve alternatively as follows:
    Taking value of π\pi as 3.143.14, we can calculate that-
    90=π2=3.142=1.57{90^ \circ } = \dfrac{\pi }{2} = \dfrac{{3.14}}{2} = 1.57and
    180=π=3.14{180^ \circ } = \pi = 3.14
    Now we know that 22lies between the above two values i.e.
    1.5723.141.57 \leqslant 2 \leqslant 3.14
    This means that the value of sec2\sec 2lies between 90{90^ \circ } and 180{180^ \circ } i.e. in Quadrant II where sec<0\sec < 0.
    Hence, we can say that b<0b < 0.
    Since sec2\sec {2^ \circ } is positive and lying in Quadrant I, we can conclude that:
    b<a\Rightarrow b < a

  2. Followings points should be remembered in case of quadrants:
    In Quadrant I: All trigonometric functions are positive.
    In Quadrant II: Only sin\sin and cosec\cos ec trigonometric functions are positive.
    In Quadrant III: Only tan\tan and cot\cot trigonometric functions are positive.
    In Quadrant IV: Only sec\sec and cos\cos trigonometric functions are positive.