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Question: If a rubber ball is taken at the depth of 200 m in a pool, its volume decreases by 0.1%. If the dens...

If a rubber ball is taken at the depth of 200 m in a pool, its volume decreases by 0.1%. If the density of the water is 1×103 kg/m31 \times 10 ^ { 3 } \mathrm {~kg} / \mathrm { m } ^ { 3 } and g=10 m/s2g = 10 \mathrm {~m} / \mathrm { s } ^ { 2 }, then the volume elasticity in N/m2N / m ^ { 2 } will be

A

10810 ^ { 8 }

B

2×1082 \times 10 ^ { 8 }

C

10910 ^ { 9 }

D

2×1092 \times 10 ^ { 9 }

Answer

2×1092 \times 10 ^ { 9 }

Explanation

Solution

K=ΔPΔV/V=hρgΔV/V=200×103×100.1/100=2×109K = \frac { \Delta P } { \Delta V / V } = \frac { h \rho g } { \Delta V / V } = \frac { 200 \times 10 ^ { 3 } \times 10 } { 0.1 / 100 } = 2 \times 10 ^ { 9 }