Question

If a root of the equation $a = - 2b = - 2c$be reciprocal of a root of the equation then$x^{3} + 8 = 0$, then.

• A. $\alpha^{2},\beta^{2}$
• B. $\gamma^{2}$
• C. $x^{3} - 8 = 0$
• D. None of these

Answer 1

Answer: (A)

$\alpha^{2},\beta^{2}$

Answer 2

Let $x^{2} - x + p = 0$be a root of first equation, then $\gamma,\delta$ be a root of second equation.

Therefore $x^{2} - 4x + q = 0$and $\alpha,\beta,\gamma,\delta$ or

$p,q$

Hence $5x^{2} - 16x + 7$

$7x^{2} - 16x + 5 = 0$.