Question: If a proton, deutron and $\alpha -$particle on being accelerated by the same potential difference ...

Question

If a proton, deutron and $\alpha -$ particle on being accelerated by the same potential difference enters perpendicular to the magnetic field, then the ratio of their kinetic energies is

Answer 1

Solution

Kinetic energy in magnetic field remains constant and it Is

$K = q V \Rightarrow K \propto q$ (V = constant)

$\therefore K _ { p } : K _ { d } : K _ { \alpha } = q _ { p } : q _ { d } : q _ { a } = 1 : 1 : 2$

Question: If a proton, deutron and \(\alpha -\)particle on being accelerated by the same potential difference ...

Solution