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Question: If a proton and anti-proton come close to each other and annihilate, how much energy will be release...

If a proton and anti-proton come close to each other and annihilate, how much energy will be released.

A

1.5×10−10J1.5 \times 10^{- 10}J

B

3×10−10J3 \times 10^{- 10}J

C

4.5×10−10J4.5 \times 10^{- 10}J

D

None of these

Answer

3×10−10J3 \times 10^{- 10}J

Explanation

Solution

Mass of proton = mass of antiproton

=1.67×10−27kg=1amu= 1.67 \times 10^{- 27}kg = 1amu

Energy equivalent to 1 6muamu=931 6muMeV1\mspace{6mu} amu = 931\mspace{6mu} MeV

So energy equivalent to 2 amu =2×931 6muMeV= 2 \times 931\mspace{6mu} MeV

=1862×106×1.6×10−19=2.97×10−10J= 1862 \times 10^{6} \times 1.6 \times 10^{- 19} = 2.97 \times 10^{- 10}J =3×10−10J= 3 \times 10^{- 10}J.