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Question: If a point object is placed under a glass slab of thickness d. If distance of image formed is 2 cm f...

If a point object is placed under a glass slab of thickness d. If distance of image formed is 2 cm from object when seen from above. If speed of light in this glass slab is 2 × 108 m/s. Then value of d is –

A

3 cm

B

6 cm

C

4 cm

D

9 cm

Answer

6 cm

Explanation

Solution

m = cv=3×1082×108=32\frac { \mathrm { c } } { \mathrm { v } } = \frac { 3 \times 10 ^ { 8 } } { 2 \times 10 ^ { 8 } } = \frac { 3 } { 2 }

x = t(1−1μ)\left( 1 - \frac { 1 } { \mu } \right) Ž 2 = t(1−13/2)\left( 1 - \frac { 1 } { 3 / 2 } \right)

\ 2 = Ž t = 6 cm