If a plane meets the coordinate axes at A, B and C in such a... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

If a plane meets the coordinate axes at A, B and C in such a way that the centroid of triangle ABC is at the point (1, 2, 3) then the equation of the plane is

A

$\frac{x}{1}+\frac{y}{2}+\frac{z}{3}=1$

B

$\frac{x}{3}+\frac{y}{6}+\frac{z}{9}=1$

C

$\frac{x}{1}+\frac{y}{2}+\frac{z}{3}=\frac{1}{3}$

D

$\frac{x}{1}-\frac{y}{2}+\frac{z}{3}=-1$

Answer

$\frac{x}{3}+\frac{y}{6}+\frac{z}{9}=1$

Explanation

Solution

The correct answer is (B) : $\frac{x}{3}+\frac{y}{6}+\frac{z}{9}=1$ .