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Question

Question: If a plane cuts off intercepts –6, 3, 4 from the co-ordinate axes, then the length of the perpendicu...

If a plane cuts off intercepts –6, 3, 4 from the co-ordinate axes, then the length of the perpendicular from the origin to the plane is

A

161\frac { 1 } { \sqrt { 61 } }

B

1361\frac { 13 } { \sqrt { 61 } }

C

1229\frac { 12 } { \sqrt { 29 } }

D

541\frac { 5 } { \sqrt { 41 } }

Answer

1229\frac { 12 } { \sqrt { 29 } }

Explanation

Solution

Equation is x6+y3+z4=1\frac { x } { - 6 } + \frac { y } { 3 } + \frac { z } { 4 } = 1 or 2x+4y+3z=12- 2 x + 4 y + 3 z = 12

\therefore Length of perpendicular from origin

=124+16+9=1229= \frac { 12 } { \sqrt { 4 + 16 + 9 } } = \frac { 12 } { \sqrt { 29 } }.