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Question

Question: If a perpendicular distance of a point \[P\] from the \[{x \ axis}\] is \[5 \ units\] and the foot o...

If a perpendicular distance of a point PP from the x axis{x \ axis} is 5 units5 \ units and the foot of the perpendicular lies on the negative direction of the x axis{x \ axis}. The point PP has

Explanation

Solution

In the given question, it’s given that the perpendicular distance of a point PP from the x axis{x \ axis} has 5 units5 \ units. We need to find the coordinate of P in this question.Perpendicular distance is nothing but the shortest distance from the point to the line.

Complete answer: We know that the perpendicular distance of a point from the x axis{x \ axis} gives x axis{x \ axis} coordinate of that point .
.i.e). xx coordinate is always perpendicular to the y axis{y \ axis}

Here the foot of the perpendicular lies in the negative direction of x axis{ x \ axis}, so the perpendicular distance can be measured in ll quadrant or lll quadrant.
From this we can conclude that the point PP has yy co-ordinate =5 or 5= 5 \ or \ - 5
The point PP has ordinate = 5 or 5= \ 5\ or\ - 5
Final answer :
The point PP has ordinate = 5 or 5= \ 5\ or\ - 5

Note:
The shortest distance of one point from the plane is called the perpendicular distance of that point. Basically there are two methods to calculate the perpendicular distance of a point . They are
-Vector method
-Cartesian method
We need to be careful that by mistake we might think the  y\ y -coordinate is the perpendicular distance from the yy -axis but it is not, the xx -coordinate is the perpendicular distance from the yy - axis. First we need to know that the horizontal axis is known as xx axis and the vertical axis is known as the yy axis.