If a normal chord at a pointegral "t" on the parabola (y^2 =... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

If a normal chord at a point "t" on the parabola $y^2 = 4ax$ subtends a right angle at the vertex, then t =

A

1

B

$\sqrt{2}$

C

2

D

$\sqrt{3}$

Answer

$\sqrt{2}$

Explanation

Solution

Normal chord at a point $'t'$ on the parabola $y^2 = 4 \,ax$ subtends a right angle at the vertex. $\Rightarrow t^2 = 2$ $\Rightarrow t = \sqrt 2$