Question

If a monovalent metal ion carries $1.6 \times {10^{ - 19}}$ coulomb of electricity, what is the amount of electricity carried by one gram of molecular mass of the metal ions?
$A)9.6336 \times {10^4}coulomb \\\ B)10.6336 \times {10^4}coulomb \\\ C)95.336 \times {10^4}coulomb \\\ D)96.336 \times {10^4}coulomb \\\$

Answer 1

To calculate the amount of electricity carried by one gram molecular mass of metal ions we multiply it with the Avogadro number. Avogadro's number is defined as the number of elementary particles per mole of a substance. It is equal to $6.023 \times {10^{23}}mo{l^{ - 1}}$ and is expressed as the symbol ${N_A}$. Avogadro's number is a similar concept to that of a dozen or a gross.

Complete answer: Charge carriers are particles or holes that freely move within a material and carry an electric charge. In most electric circuits and electric devices, the charge carriers are negatively charged electrons that move under the influence of a voltage to create an electric current.
Any free carriers of electric charge in the liquid, and the liquid, therefore, conducts electricity. Such carriers are of two kinds: mobile electrons and ions.
The molecular mass is the mass of a given molecule. Different molecules of the same compound may have different molecular masses because they contain different isotopes of an element.
Charge on $1$ metal ion$= 1.6 \times {10^{ - 19}}$
Charge on $1$ gram molar mass $= 1.6 \times {10^{ - 19}} \times 6.023 \times {10^{23}}$
Charge on $1$ molar mass $= 9.6336 \times {10^4}$
So, the correct answer is $A)9.6336 \times {10^4}coulomb$.

Note:
Carrier generation describes processes by which electrons gain energy and move from the valence band to the conduction band, producing two mobile carriers; while recombination describes processes by which a conduction band electron loses energy and re-occupies the energy state of an electron hole in the valence band.