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Question

Physics Question on Motion in a straight line

If a man goes 10m10 \,m toward north and 20m20\, m toward east, then his displacement is

A

22.5m22.5\, m

B

25m25\, m

C

25.5m25.5\, m

D

30m30\, m

Answer

22.5m22.5\, m

Explanation

Solution

Displacement =AC=(AB)2+(BC)2=AC=\sqrt{\left(AB\right)^{2}+\left(BC\right)^{2}} =(10m)2+(20m)2=\sqrt{\left(10\,m\right)^{2}+\left(20\,m\right)^{2}} =100+40022.5m=\sqrt{100+400} \approx 22.5\,m